passing array to a function by declaring pointers in the function

#include <stdio.h>
int fun1(int* ptr)
{
  for (int i = 0; i < 4; ++i) {
    printf("The value of %d is %d\n",i,ptr[i]); //or
    printf("The value of %d is %d\n",i,*(ptr+i)); // both do the same work
  }
  *(ptr+2)=58; //value gets changed of 2nd index of array
}
int main ()
{
int arr[]={2,4,6,8};
fun1(arr);
fun1(arr);
  return 0;
}